chemistry homework

Question

A silver ring is composed of 2.71×1023 atoms.2.71×1023 atoms. Calculate the mass of the ring in grams.

Answer 1

This looks like a dimensional analysis problem.

Assuming that you are trying to find the mass of a ring comprised of 2.72 × 10²³ silver atoms, here's what you need to do:

1. Divide the number of atoms by Avogadro's number (6.022 × 10²³ particles/mol) to determine how many moles of silver are in the ring. The 10²³ parts of the numbers will cancel so this amounts to calculating that you have (2.72 ⁄ 6.022) moles of silver in the ring.
2. Multiply moles of silver in the ring by the atomic mass of silver, which is 107.8682 g/mol, to convert moles to grams.

So the mass of the ring is (2.72 ⁄ 6.022) mol × 107.8682 g/mol = 48.7 g (rounded to 3 significant figures).

Answer 2

There appears to be missing information in the question. Please check your source & resubmit.