Jerome S. answered 09/04/23
PhD in Inorganic Chemistry with 10+ years of online tutoring experienc
(6.5-5.91) the signifcant figure is in the tenth's place = 0.59 with 1 sig fig
0.59/3.83 = 0.154... with 1 significant figure since it's the least between 1 sig fig in the numerator and 3 sig figs in the denominator
0.154 the figure to the right of the significant figure is 5 or more so round up.
answer 0.2 just 1 sig fig