Transmittance Question

Question

A 0.0195 M solution of a certain analyte exhibits 41.8% 𝑇 at a wavelength of 280 nm. What will the percent transmittance be for a 0.0251 M solution of the same analyte? Assume the path lengths for each measurement are equal.

This the second part of the question the first part asked for an absorbance of 41.8%T which I got correct and calculated as 0.378.

I and struggling to find the %T for the second part as there is no pathlength or molar absorb number. any advice?

Answer 1

Absorbance for the first part can be calculated as follows:

A = -logT , T = 41.8/100 = 0.418

A = -log (0.475) = 0.378

Second part:

A₂/A₁ = C₂/C₁

A₂ = (0.0251 M /0.0195 M) x 0.378 = 0.487

T = 10^(-0.487) = 0.325 = 32.5 %