Anthony T. answered 08/01/23
Considering the reaction given, you get 2 bromide ions for every lead ion in solution, so if the concentration of Pb2+ is symbolized by X, then the Br- concentration is 2X.
The equilibrium equation can be written Ksp = [X[ [2X]2. Substitute the given value of Ksp in the equation and solve for X which is the Pb2+ concentration and 2X is the Br1- concentration.
X = (2.10 x 10-6 / 4)1/3 = 8.07 x 10-3 M
Anthony T.
Sorry to have taken so long to answer your comment. Where other non-common ions are present, the equilibrium equation must be solved using activities instead of concentrations. As I am not a physical chemist, I can't give you a detailed explanation, but the calculation becomes more complicated.08/04/23
Yash P.
is this when the ionic strength is 0? How would I do it for 0.01M ionic strength?08/01/23