What is the density of 15 M NaOH

Answer 1

One can take 15 M NaOH as equivalent to 15 mol/L NaOH. We know that density equals mass/Volume, in SI units of kg/m³ or kg/L for aqueous, liquids, or solids. Therefore, 15 mol/L of NaOH can be stoichiometrically converted to grams/L and then to kg/L which would give us the SI units of density.

Looking at the periodic table, we can determine the overall molecular weight or g/mol of NaOH by summing the g/mol of each atomic species, Na is ~23 g/mol, O is ~16.00g/mol, and H is ~ 1.0 g/mol. The total molecular weight or amu of NaOH is thus ~40g/mol.

Stoichiometry Table:

15 mol/L NaOH x (40.0 g/mol) --> cancels the moles and leaves us with 600 g/L NaOH

which may subsequently be converted into kg/L, the SI unit of density:

600 g/L x (1kg/1000g) = 0.6 kg/L. Thus, the density is 0.6 kg/L or 0.6kg/m³.

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