should a polar or nonpolar solvent be used to dissolve solid NH4OH? Why?

Question

I tried drawing the lewis structures of NH4 and OH. Does Nh4 have an expanded octet and if it does what will the drawing look like? Would it be polar ( one extra electron) or non polar ( tetrahedral shape)?

Answer 1

You missed the main theme here. Ammonium hydroxide is ionic. It is NH₄⁺ and OH^- floating in water (with NH₃ in equilibrium). Ammonia is very polar and ammonium hydroxide is a base: They both dissolve strongly in water by both ionization and hydrogen bonding between NH3 and water.

NH₄⁺ is isoelectronic with CH₄ (tetrahedral and very much following octet rule).