Bradford T. answered 06/08/23
Retired Engineer / Upper level math instructor
Work = Force×Distance
Force = Density×Volume, Density=ρ=1050
Put the vertex of the inverted cone at the origin of the x-y axis.
Using a small disk
Volumedisk = area×Δy = πx2Δy
By similar triangles, x/y = 3/7 --> x = (3/7)y
Volumedisk = π(9/49)y2Δy
Distance to move a small disk over the top = 7-y
Work = πρ(9/49)∫50(7-y)y2dy = πρ(9/49)∫507y2-y3dy = πρ(9/49)[7y3/3-y4/4]50
≈ 82046.1 Joules