How many moles of rust iron (lll) oxide are produced when 15g of iron reacts with enough oxgen?

Answer 1

21.56g

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Answer 2

Iron (III) oxide is formed according to the following balanced chemical equation: 4Fe(s)+3O2(g)→2Fe2O3(s)

15g of Iron is equivalent to [(15.000) / (55.845g/mol)] or 0.2686 moles.

For every 4 moles of iron we produce 2 moles of rust, i.e. half.

0.2686 moles of iron in, 0.1343 moles of iron oxide out.