Belinda H.
asked 05/17/23If the starting temp is -50c the mass of copper is 25g and the infared view is 23.9c
Identify the expected cold temperature when it is removed from the cold water using this equation Q=mc🔺T
1 Expert Answer
Neeraj S. answered 05/25/23
Neerajrockstar00000000
To find the expected cold temperature when the copper is removed from the cold water, we can use the equation Q = mcΔT
where:
Q represents the heat gained or lost by the object (copper in this case),
m is the mass of the object (25 g),
c is the specific heat capacity of the material (copper),
ΔT is the change in temperature.
Since the copper is being removed from cold water, it will lose heat, so Q will be negative.
To calculate the change in temperature, we can rearrange the equation as follows:
ΔT = Q / (mc)
To determine Q, we need to calculate the heat gained or lost by the copper. The initial temperature of the copper is -50°C, and the infrared view is 23.9°C, so the change in temperature is:
ΔT = 23.9°C - (-50°C) = 23.9°C + 50°C = 73.9°C
Now, we can substitute the values into the equation to find the expected cold temperature when the copper is removed from the cold water:
ΔT = Q / (mc)
73.9°C = Q / (25 g * c)
To calculate the expected cold temperature, we need the specific heat capacity (c) of copper. The specific heat capacity of copper is approximately 0.39 J/g°C.
Substituting the values into the equation:
73.9°C = Q / (25 g * 0.39 J/g°C)
Now, to find Q, we can rearrange the equation as:
Q = 73.9°C * (25 g * 0.39 J/g°C)
Q ≈ 723.975 J
Substituting the value of Q back into the equation:
723.975 J = (cold temperature - 23.9°C) * (25 g * 0.39 J/g°C)
Simplifying the equation:
723.975 J = (cold temperature - 23.9°C) * 9.75 J
Q = 73.9°C * (25 g * 0.39 J/g°C)
Q ≈ 723.975 J
Substituting the value of Q back into the equation:
723.975 J = (cold temperature - 23.9°C) * (25 g * 0.39 J/g°C)
Simplifying the equation:
723.975 J = (cold temperature - 23.9°C) * 9.75 J
ANSWER IS
Therefore, the expected cold temperature when the copper is removed from the cold water is approximately 98.209°C.
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Belinda H.
So meant to put physics05/17/23