Joy A. answered 05/13/23
College Student Good in Writing
ΔQ = Specific Heat *mass *ΔT
ΔQ= Heat absorbed or released
specific heat = 4.184 J/g-K
mass = 12.13g
ΔT = (53.0 - 43.0)°C = 10.0°C
Find change of heat in water:
ΔQ = 4.184 J/g-K * 12.13g * 10 C
= 507.5 J
The heat absorbed by the metal = - Heat change of water = -507.5 J
Therefore, the specific heat of metal, Cmetal = (-507.5 J)/(168.6 * (53.0 - 87.1) = 0.088 J/g-C