
Sidney P. answered 05/12/23
Astronomy, Physics, Chemistry, and Math Tutor
Stoichiometry: (23.87g AgNO3) * (1 mole AgNO3 / 169.87g AgNO3) * (1 mole Zn(NO3)2 / 2 mole AgNO3) = 0.070 mole Zn(NO3)2.
Sydney J.
asked 05/12/23How many moles of Zn(NO3)2 are produced from 23.87 grams of AgNO3 and excess Zn? Round your answer to three digits after the decimal point.
Zn + 2 AgNO3 à 2 Ag + Zn(NO3)2
Sidney P. answered 05/12/23
Astronomy, Physics, Chemistry, and Math Tutor
Stoichiometry: (23.87g AgNO3) * (1 mole AgNO3 / 169.87g AgNO3) * (1 mole Zn(NO3)2 / 2 mole AgNO3) = 0.070 mole Zn(NO3)2.
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