What volume does 1.17 mol of N2 gas occupy at a temperature of 108°C and a pressure of 453 mm Hg?

Answer 1

Use the Ideal Gas Law:

PV = nRT or V = nRT/P

where:

n = 1.17 mol

R = 62.364 L•mmHg/(K•mol)

T = 103 + 273.15 = 376.15 K

P = 453 mm Hg

V = (1.17)(62.364)(376.15)/453 = 60.6 liters