What is the temperature (in °C) if 22.1 g of N2 in a 1.1 L container has a pressure of 22.5 atm?

Answer 1

Use the Ideal Gas Law

PV = nRT or T = PV/(nR)

To find the number of moles (n), use the molar mass. N2 = 14.007(2) = 28.014 g/mol. and (22.1 g)/(28.014 g/mol) = 0.7889 moles

Use R = 0.08206 (L•atm)/(K•mol)

So:

T = PV/(nR)

T = (22.5•1.1)/(0.7889•0.08206) = 24.75/0.06474 = 382.32 K

Convert to °C by subtracting 273.15

T = 382.32 - 273.15 = 109.17 °C

It would be appropriate to round to 2 sig figs so T = 110 °C