What amount of heat, in kJ, is required to vaporize 108.30 g of ethanol (C₂H₅OH)? (∆Hvap = 43.3 kJ/mol)

Question

need answer to this question. answer must be in significant figures.

Answer 1

In order to do this first you must use the molar mass of ethanol to convert grams to moles and then use the heat of vaporization given to convert moles to kJ. This would be set up as follows:

108.30 g *(1 mol/46.07g)*(43.3kJ/1mol)=101.79kJ