How do you calculate volume or concentration in an Acid base neutralization reaction?

Question

V_aS_a/V_bS_b=n_a/n_b. Here, V_a=volume of acid, S_a=Concentration of Acid, n_a=number of moles of acid. similarly V_b=volume of base, S_b=Concentration of base

The above formula could be useful

Answer 1

V_aS_a/V_bS_b=n_a/n_b.

Here, V_a=volume of acid, S_a=Concentration of Acid, n_a=number of moles of acid. similarly

V_b=volume of base, S_b=Concentration of base