Chemistry Homework

Question

A 45.0 mL solution of LiOH is neutralized with 35.1 mL of 0.350 M HCl. What is the concentration of the original LiOH solution?

Answer 1

To answer this question, you have to remember that when an acid-base neutralization occurs, at the point when the solution is neutralized or the equivalence point, the moles of acid equal the moles of base. So as long as they react in a one to one mole ratio you can use the following equation:

M₁V₁ = M₂V₂

(35.1 mL) (0.350 M) = M₂ (45.0 mL)

Solving for M₂ you get 0.273 M.