How much water should be added to 139.2 mL of 18.0 M H2SO4 to prepare a 3.1 M solution?

Answer 1

You can use the equation... M₁V₁ = M₂V₂

M₁ = molar concentration of starting solution

V₁ = volume of starting solution in L

M₂ = molar concentration of final solution

V₂ = volume of final solution in L

Plugging the numbers into the equation give us .... (18)(0.1392) = (3.1)V₂

Now Solve for V₁

V₂ is the total volume of the final solution, which means you need to subtract the starting volume (V₁) from V₂. That will tell you how much additional water you need to add.

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