Enter the nuclear equation

Question

Enter the nuclear equation for the alpha decay of polonium-216 (216 PO

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Answer 1

The alpha decay of polonium-216 (216Po) can be represented by the following nuclear equation:

^216Po --> ^4He + ^212Pb

In this equation, an alpha particle (^4He) is emitted from the nucleus of polonium-216, resulting in the formation of a new nucleus of lead-212 (^212Pb). The atomic number of the polonium nucleus decreases by 2 due to the emission of an alpha particle, while the mass number decreases by 4.