Calculate the number of moles of NH3(g) produced when 0.150 mol N2 is allowed to react with 0.430 mol H2(g). N2(g) + 3 H2(g)  2 NH3(g)

Question

please help!!!

Answer 1

The first step is realizing that if you want 0.150 moles of N₂ to react, you would need 0.450 moles of H₂ (you need three times as many moles of N₂).

Since there is only 0.430 moles of H₂ , that is what limits the reaction, and we will use that value in our calculation.

The equation tells us that for every 3 moles of H₂ consumed, we get 2 moles of NH₃ product.

In other words, you take the number of moles of H₂ and multiply it by (2/3) to get the number of moles of NH₃

0.430(2/3) = 0.28666666

Final answer: 0.287 moles of NH₃ is produced

Hope this helped. Please feel free to reach out if you have any other questions :)