Stuck on chemistry problem due tonight

Question

How many joules are required to melt 48 grams of Ammonia (NH3)? The heat of fusion of ammonia is 5.66kJ / m * ole Round to the appropriate amount of significant figures

Answer 1

The value for the heat of fusion tells you how much energy is required to melt a mole of a substance.

Therefore, you need to figure out how many moles of ammonia you have and then multiply that by the heat of fusion.

I got an answer of 16.00 kJ of energy.

A simple example may be easier to follow. If I have 2 moles of substance A, and it has a heat of fusion of 10 kJ/mole, that means I would need 20 kJ of energy to melt all of substance A. Hopefully it is more obvious why you would multiply the two values.

If you have any questions, or would like me to explain myself farther, please feel free to reach out.