Inactive Tutor answered 04/25/23
Tutor
New to Wyzant
(-2,7) is in quadrant II, with hypotenuse = sqr(4+49) =sqr53
cosT = -2/sqr53 = -2sqr53/53
sinT = 7/sqr53 = 7sqr53/53
cotT = -2/7
Zachary M.
asked 04/25/23Inactive Tutor answered 04/25/23
(-2,7) is in quadrant II, with hypotenuse = sqr(4+49) =sqr53
cosT = -2/sqr53 = -2sqr53/53
sinT = 7/sqr53 = 7sqr53/53
cotT = -2/7
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