Chemistry Stoichiometric Relationship

Question

7. A solution of 0.65 mol/dm³ NaCl contains 2.3g. What volume of water was the NaCl dissolved in?

Answer 1

To determine the volume of water that the NaCl was dissolved in, we can use the relationship between concentration, amount of substance, and volume:

concentration = amount of substance / volume

Rearranging this equation, we get:

volume = amount of substance / concentration

First, let's calculate the amount of substance of NaCl in 2.3g:

amount of substance = mass / molar mass

The molar mass of NaCl is 58.44 g/mol, so:

amount of substance = 2.3g / 58.44 g/mol amount of substance = 0.0394 mol

Now we can use the given concentration of 0.65 mol/dm3 and the calculated amount of substance to find the volume of water:

volume = amount of substance / concentration volume = 0.0394 mol / 0.65 mol/dm3 volume = 0.06 dm3 or 60 mL

Therefore, the NaCl was dissolved in 60 mL of water.