A 6.22-kg piece of copper metal is heated from 20.5°C to 324°C. Calculate the heat absorbed (in kJ) by the metal.

Answer 1

The heat absorbed by the metal can be calculated using the formula:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the metal, c is the specific heat capacity of copper, and ΔT is the change in temperature.

The specific heat capacity of copper is 0.385 J/g°C, which can be converted to kJ/kg°C by dividing by 1000 and multiplying by the mass of one kilogram:

c = 0.385 J/g°C x (1 kg / 1000 g) = 0.385 kJ/kg°C

Substituting the values given:

Q = (6.22 kg) x (0.385 kJ/kg°C) x (324°C - 20.5°C)

Q = 6.22 x 0.385 x 303.5

Q = 720.7 kJ (rounded to three significant figures)

Therefore, the heat absorbed by the metal is 720.7 kJ.