J.R. S. answered 04/16/23
First, we'll determine the moles of Ni that were plated out.
39.2 g Ni x 1 mole Ni / 58.7 g = 0.6678 moles Ni
Next, we'll figure out how many moles of electrons were associated with this:
2 F x 1 mol e- / F = 2 moles of electrons.
Finally, we can determine the charge on the nickel:
2 moles electrons / 0.6678 moles Ni = 2.99 = 3 moles of electrons per mole Ni plated out.
ANSWER = (C) Ni3+
Ni3+(aq) + 3e- ==> Ni(s)