Step by step chemistry problem due tonight

Question

You are trying to determine the concentration of a stock solution of hydrochloric acid. You have 450.80 mL of 0.86 M dilute solution that was prepared with 25.50 of stock solution

Answer 1

Hi,

It seems you know the volume of the stock solution that was used (25.5ml). You could use the C1xV1=C2xV2 rule. In this case, it will be 0.86M x 450.80mL = C2 x 25.50mL. Rearranging that will give you:

15.203M of stock solution. Let me know if I missed anything :-)