Need some chem help please

Question

How much 1.20 M NaOH will be needed to neutralize 225 mL of 3.0 M H2SO4(aq) ?

a. 0.045 L

b. 0.28 L

c. 0.56 L

d. 0.90 L

e. 1.1 L

anything will help!

Answer 1

Let's say, Volume of NaOH = V1, Concentration of NaOH = M1 =1.2M, Volume of H2SO4 = V2 = 225 mL, Concentration of H2SO4 = M2 = 3.0M.

The neutralization reaction is as follows:

2NaOH + H2SO4 = Na2SO4 + 2H2O

Since NaOH reacts with H2SO4 in a 2:1 ratio, the formula is (M1 * V1)/2 = (M2 * V2)/1

M1*V1 = 2*M2*V2

V1 = (2*M2*V2)/M1

V1 = 1125 mL = 1.125L (e)