What is the change in enthalpy when 1.50 moles of H2 are reacted with an excess O₂ of according to the following balanced chemical reaction: 2H₂(g)+O₂(g)→2H₂O(l) ∆H=-572 kj

Answer 1

Hello Amy,

The change in enthalpy mentioned in the problem is specific to a reaction involving 2 moles of H₂. In order to determine the change in enthalpy for a reaction involving 1.50 moles of H₂, you will need to perform the following calculation:

1.50 mol H₂ * (-572 kJ / 2 mol H₂) = -429 kJ

We would expect the enthalpy change to be lower since there are fewer new bond formations when we only have 1.50 moles of H₂ to react. I hope this helps!

Sincerely,

Michael