Combining 0.332 mol Fe2O3 with excess carbon produced 13.0 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual and theoretical yield of iron in moles?

Answer 1

Fe₂O₃ + 3C ⟶ 2Fe + 3CO

This equation states that for every mole of Fe₂O₃ used, there are 2 moles of Fe that are produced. So, if 0.332 moles of Fe₂O₃ are used, then (0.332)(2) or 0.664 moles of Fe are produced. That's the theoretical yield.

The actual yield was 13.0 g. Using the period table, the molar mass of iron is 55.845 g/mol. To determine the number of moles that 13.0 g is, divide 13.0 by 55,845 and you get 0,233 moles. That is the actual yield.