Potassium metal reacts with water according to the following balanced equation. 2K(s)+2H2O(l)⟶2KOH(aq)+H2(g) How many moles of KOH are produced if 2963.1 moles of H2O are consumed?

Answer 1

In the equation, 2 moles of water will react to form 2 moles of KOH. So if you react 5 moles of water, you will form 5 moles of KOH. Same for your question. If you react 2963.1 moles of water, you will get 2963.1 moles of KOH.

This one seems almost too simple only because the water and KOH have the same coefficient in the balanced equation. If they had different coefficients (like water and the H₂), you would have to use a ratio (half the coefficient of water for H₂).