Capacitors And potential difference

Question

Two capacitors, C₁ = 24.0 𝜇F  and C₂ = 33.0 𝜇F, are connected in series, and a 24.0-V battery is connected across them.

(a) Find the equivalent capacitance, and the energy contained in this equivalent capacitor.

(b) Find the energy stored in each individual capacitor. (C1 and C2 in joules)

(c) If the same capacitors were connected in parallel, what potential difference would be required across them so that the combination stores the same energy as in part (a)? 

Answer 1

Ceq= C1C2/(C1+C2)= 13.9 μF ... Energy = 1/2CeqV²= .004 Joule a)

Charge on each will be the same when in series and is Q=CeqV=.00334 coulomb. V1=.000334/24E-6=13.9 v and V2=10.1 volts. Thus the energy stored in C1=.00232 J and C2 = .00172 J b)

Ceq in parallel is the same of the two = 57 μF. If the total energy = .00404 J then V = 11,9 volts c)