chemistry balanced equation

Question

To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process.

Answer 1

Pb⁺²S^-2 + O⁰₂ → Pb⁰ + S⁺⁶O^-2₃

1. Decreased valence: Pb(+2→0), O(0→-2); Increased valence: S(-2→6);
2. For charge balance: for one unit of Pb and S, 2+2x =8, x=3 unit of O involved in reaction;
3. Therefore: PbS + (3/2)O₂ → Pb + SO₃
4. Integralize all factors of the reaction equation: 2PbS + 3/O₂ → 2Pb + 2SO_3.