Jennifer M. answered 05/30/23
We will use mcΔT for this problem. We will have one variable: the specific heat of the metal that we will call cm.
First, set up the equation.
25g(cm)(20.15°C-99°C)+50g(4.814 J/g°C)(20.15°C-8.7°C)=0
-1971cm + 2756=0
-1971cm = -2756
cm=1.398 J/g°C, which is 1.40J/g°C, taking significant figures into account.
Answer: 1.40 J/g°C