Calorimetry.....

Question

An unknown sample is being evaluated in lab. What is the specific heat capacity of the compound if it requires 372.19 J to raise the temperature of 78.36 grams of the unknown from 15.2 °C to 34.5 °C

Answer 1

The specific heat capacity (c) of a substance is defined as the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius.

In this case, we need to calculate the specific heat capacity of the unknown substance using the given information.

The formula to calculate the heat energy required to raise the temperature of a substance is:

Q = m * c * ΔT

where: Q = heat energy (in Joules) m = mass of the substance (in grams) c = specific heat capacity of the substance (in J/g°C) ΔT = change in temperature (in °C).

--------------------------------------------------------------------------------------------------------------------------------------------------

Using the given values, we can rearrange the formula to solve for c:

c = Q / (m * ΔT)

Substituting the given values:

c = 372.19 J / (78.36 g * (34.5°C - 15.2°C))

c = 372.19 J / (78.36 g * 19.3°C)

c = 0.25 J/g°C

Therefore, the specific heat capacity of the unknown substance is 0.25 J/g°C.