Calorimetry.....

Question

Calculate the internal energy (in Joules) of an endothermic system that absorbs 356.3 J and expands from 1.00 to 6.830 L against a pressure of 5.48 atm.

Answer 1

ΔE = ΔH - PΔV

ΔH = 356.3 J

P = 5.48 atm = 555261 Pa

ΔV = 6.83 - 1.00 = 5.83L = 0.00583 m³

ΔE = 356.3 - (555261 x 0.00583) = - 2880.8 J