A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s.

Question

(a) What is the length of this pipe?

(b) What are the next two harmonics?

(c) What is the fundamental frequency of this pipe when the speed of sound in air is increased to 370 m/s due to a rise in the temperature of the air?

Answer 1

fn=nv/4L thus 320 = 1*331/4L. Solve to find L = 331/1240 meters a)

b) 320*3=960 Hz and 320*5=1540 Hz

c) f1=370/4L = 370/4/331*1240 Hz