what is the heat required

Question

How much heat (in joules) is required to raise the temperature of 50.0 mL of water from 17.3 °C to 34.7 °C? Answer to 1 decimal place with no units.

Answer 1

q = mC∆T

q = heat = ?

m = mass = 50.0 ml x 1 g / ml = 50.0 g (assuming a density of 1 g/ml for water)

C = specific heat for water = 4.184 J/gº

∆T = change in temperature = 34.7 - 17.3º = 17.4º

Solving for q ...

q = (50.0 g)(4.184 J/gº)(17.4º)

q = 3640.1