
David B. answered 08/15/23
Math and Statistics need not be scary
The timing of radioactive decay is an example of the exponential distribution with the distribution parameter lambda (λ)
λ = 1/ average event rate = 1/13 = 0.291 per millisecone
Using the cumulative exponential distribution the probability of a time between decays being 4 or more milliseconds is
P(X > x) = e-xλ or e-(4·.291) or .312