Amy S.

asked • 03/22/23

Determine the limiting reagent of MgO(s)+2HCl(aq)= MgCl2(aq)+H2O

J.R. S.

tutor
In the current problem you don't supply the mass or moles of the reactants, so we cannot determine the limiting reagent.
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03/22/23

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Mishka G. answered • 03/22/23

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If MgO is the limiting reagent:

10 g MgO * (1 mol MgO / 40.3044 g) * (1 mol MgCl2 / 1 mol MgO) = 0.248 mol MgCl2


If HCl is the limiting reagent:

10 g HCl * (1 mol HCl / 36.458 g) * (1 mol MgCl2 / 2 mol HCl) = 0.137 mol MgCl2


0.137 mol is less than 0.248 mol, therefore HCl is the limiting reagent.

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J.R. S.

tutor
Where did you come up with 10 g of each reactant? Was that provided in the question?
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03/22/23

Mishka G.

No it is simply a comparison point. Another way of looking at it is the reaction consumes 2 mol of HCl for every mol of MgO, or twice as fast.
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03/22/23

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