How many grams of PCl3 are produced with 6.2g of chlorine gas reacting with excess phosphorous?

Question

_P₄ + 6Cl₂ ---> 4PCl₃

Answer 1

The balanced chemical equation shows that 1 mole of P4 reacts with 6 moles of Cl2 to produce 4 moles of PCl3.

From the given information, we know that we have 6.2 g of Cl2. We can use the molar mass of Cl2 to convert grams to moles:

moles of Cl2 = mass of Cl2 / molar mass of Cl2 moles of Cl2 = 6.2 g / 70.90 g/mol = 0.0874 mol

According to the balanced chemical equation, 1 mole of P4 reacts with 6 moles of Cl2 to produce 4 moles of PCl3.

Therefore, the number of moles of PCl3 produced is:

moles of PCl3 = moles of Cl2 / 6 x 4 = 0.0874 mol / 6 x 4 = 0.00364 mol

Finally, we can use the molar mass of PCl3 to convert moles to grams:

mass of PCl3 = moles of PCl3 x molar mass of PCl3 mass of PCl3 = 0.00364 mol x 137.33 g/mol = 0.499 g

Therefore, 0.499 g of PCl3 is produced when 6.2 g of Cl2 reacts with excess phosphorus.