Please help me solve this

Question

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 174.7-cm and a standard deviation of 0.6-cm.

Find the probability that the length of a randomly selected steel rod is greater than 173.9-cm.

P(X > 173.9-cm) = 

Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Answer 1

mean = 174.7 cm

standard dev = 0.6 cm

value = 173.9 cm

173.9 - 174.7 = -0.8

-0.8/0.6 = -1.333 standard deviations, or 1.333 standard deviations to the left of the mean. Our z-score, the number of standard deviations away from the mean, here is thus -1.333.

The probability, aka the chance we'll get values to the right of a z-score of -1.333 is 0.0918 using the z-score table. This means that the probability obtaining values greater than this, or greater than 173.9 cm, is 1 - 0.0918 = 0.9082 which is your answer.