
Lisa D. answered 03/27/23
Experienced AP Chemistry Teacher / Patient and Knowledgeable and Tutor
First calculate moles of each reactant:
3.35g Al = 0.124 mol
12.5g CuCl2 = 0.0929 mol
When you have amounts for both reactants you need to determine which one is limiting:
Divide each by its coefficient in the balanced equation and compare
0.124 mol Al / 2 = 0.62
0.0929 mol CuCl2 / 3 = 0.310 (smaller value, so this is the limiting reactant
Use the limiting reactants amount to calculate the theoretical yield of Cu:
In the balanced equation the coefficient of CuCl2 and Cu are the same, so the moles of Cu produced is the same as the moles of CuCl2 that is reacted.
0.0929 mol CuCl2 = 0.0929 mol Cu
0.0929 mol Cu = 5.90g Cu (this is the theoretical yield)
The actual yield is obtained by subtracting the filter mass from the Mass of filter paper + copper
5.30 - 1.25 = 4.05g
To answer questions about lab errors, determine which measurement will be affected by the error and then follow that through the calculation. If the filter paper was still wet then the "Mass of filter paper + copper" would be too high. This measurement was used to find the actual yield. If it is too high, then the actual yield would be too high. If the actual yield is too high then the percent yield would be too high.