Grams to energy conversion: (formula is (m/MBA) x ΔHcomb)
7.52 g BA (1 mole/88.10 g BA)(-2.18x103 kJ/mole BA) = kJ
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Maela H.
asked 03/16/23For the following combustion reaction CH₃CH₂CH₂COOH(l) + 5O₂(g) → 4CO₂(g) + 4H₂O(g) ∆H = -2.18 × 10³ kJ When a 7.52-g sample of butyric acid (molar mass = 88.10 g/mol) is burned, how much energy (in kJ) is released as heat?
Grams to energy conversion: (formula is (m/MBA) x ΔHcomb)
7.52 g BA (1 mole/88.10 g BA)(-2.18x103 kJ/mole BA) = kJ
Please consider a tutor. Take care.
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