
David B. answered 08/20/23
Math and Statistics need not be scary
Hello Lilly, you have an interesting two part problem. The first part requires the scientist / investigator (ie you) to construct a probability density (or probability mass function) for x where x is the distance of the attempted 'putt' in a range of 10 to 29 feet. where S is proportion of success in an interval and x is an interval of ranges in feet.
Part (a)
n 1 2 3 4
x 10-14 15-19 20-24 25-29
p(x) .5 .25 .15 .1
Sx .85 .65 .30 .1
The overall probability of success for putts in the 10-29 foot range is the expected value of S and is calculated using the standard equation for that
E[s) = ∑n=14 p(xn)Sn
part (b)
given the above probability mass function and Bayes Theorem P(B|A) = P(A|B)P(B)/ P(A) and the corollary that P(B|A) = P(A ∩ B) / P(A)
then given that B is a 15-19 foot putt and A is a successful putt, then the probability of B being 15-19 is easy to calculate because the p would be the number of successful putts made in the 15-19 foot range divided by the total number of successful putts made which would be p(x2) .
These are the methods for finding the answers to the questions. If you need more help in this you can request a session with me at www.wyzant.com/tutors/David4745.
The ask an expert section is not for free homework help. That is why I gave you the explanation of how to get the answer, and did not give answers. Good luck.