please help me out

Question

For a standard normal distribution, find:

P(z > -2.06)

Express the probability as a decimal rounded to 4 decimal places.

Answer 1

Assuming the 'z' stands for the z-score, refer to your z-score table and find the probability corresponding to z = -2.06. That probability is 0.0197 which means 1.97% of all the data lies past this z score value, which is about 2 standard deviations to the left of the mean.

To get the probability that we will have values greater than this z-score we need to subtract it from 1 which is the total probability of the normal distribution. Aka, the total probability - the probability of values lesser than your z-score = the probability of values greater than your z-score (P (z > -2.06))

1 - 0.0197 = 0.9803 or 98.03% of your data lies to the right of z = -2.06 which is your answer