The second order reaction A → Products takes 13.5 s for the concentration of A to decrease from 0.740 M to 0.277 M. What is the value of k for this reaction?

Answer 1

The rate equation for a second order reaction can be expressed as R = k[A]^2.

The integrated form of this equation is 1/[A] = 1/[A₀] +kt where [A] and [A₀] are the final and initial concentrations respectively.

Substituting the give values into the equation gives 1/0.277 M = 1/0.740 + kt.

Solving for k = (1/0.277 - 1/0.740) / 13.5. k = 0.167 M^-1 s^-1

Please check math.