Pascal M. answered 03/30/15
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Morgan,
To answer a question like that you need to have your solubility rules with you... so pull out your textbook and find that table or list there.
Now you have an ionic compound + an anion compound... this means that you will have double displacement reaction in which the ions will change partners.
potassium sulfate + barium nitrate --> barium sulfate + potassium nitrate
Based on the solubility rules in your book, you should be able to determine that
- all potassium salts are soluble = (aq)
- all nitrate salts are soluble = (aq)
- most sulfate salts are soluble = (aq) EXCEPT WITH lead, barium, etc... then it would be (s)
- there is no rule about barium per se... it's only an exception to other rules.
Based on this analysis, the states of your compounds should be:
potassium sulfate + barium nitrate --> barium sulfate + potassium nitrate
(aq) + (aq) --> (s) + (aq)
So, your precipitate will be barium sulfate, coming from the barium ion and the sulfate ion.... and your net ionic equation would be:
barium ion (aq) + sulfate ion (aq) ---> barium sulfate (s)
all you have to do now is to:
- write the symbols for the ions with the proper charges
- write the proper formula for your solid
- balance the equation
And tada... you are done!