Consider the reaction below: 2 SO₃(g) ⇌ 2 SO₂(g) + O₂(g) The Kp is 1.81 × 10⁻⁵ at 350.0 °C. Calculate Kc at the same temperature. (R = 0.08314 L･bar/mol･K.)

Answer 1

The relationship between Kp and Kc is given by the equation:

Kp = Kc(RT)^(Δn)

where R is the gas constant, T is the temperature in Kelvin, and Δn is the difference in the number of moles of gaseous products and reactants.

In this case, we have:

Δn = (2+1) - 2 = 1

R = 0.08314 L･bar/mol･K

T = 350.0 + 273.15 = 623.15 K

Kp = 1.81 × 10⁻⁵

Plugging these values into the equation, we get:

Kc = Kp / (RT)^Δn

Kc = (1.81 × 10⁻⁵) / ((0.08314 L･bar/mol･K)(623.15 K))^1

Kc = 2.41 × 10⁻⁵

Therefore, the value of Kc at 350.0 °C is 2.41 × 10⁻⁵.