2 Al + 3 CuCl2 → 2 AlCl3 + 3 Cu, If 0.252 moles of copper (II) chloride completely reacts, how many grams of aluminum chloride were produced in the reaction?

Question

(Molar mass of Al = 26.98 g/mol) (Molar mass of AlCl₃ = 133.34 g/mol) (Molar mass of CuCl₂ = 134.45 g/mol) (Molar mass of Cu = 63.55 g/mol)

Answer 1

1. Use mole ratio to go from moles of CuCl₂ to moles of AlCl₃
2. 0.252 mol CuCl₂ *(2 moles AlCl₃/3 mol CuCl₂) = 0.168 mol AlCl₃
3. Then, use molar mass of AlCl₃ to convert from moles to grams of AlCl₃
4. 0.168 mol AlCl₃ (133.34g AlCl₃/1 mol AlCl₃) = 2986 g AlCl₃ (rounded to sigfigs 2990 g AlCl₃)