Problem C. Mirror

Question

Problem C. Mirror

Next, you will be implementing the mirror function. This overwrites the right half of the image with a mirror image of the left (so within each list of lists representing a row of pixels, the pixels in the second half of the row are overwritten by a mirror image of the pixels in the first half). If there are an odd number of columns, the middle column remains unchanged.

Examples:

>>> mirror([[[127, 127, 127], [0, 0, 0]],

[[255, 255, 0], [50, 128, 255]],

[[0, 0, 255], [0, 255, 0]],

[[255, 0, 0], [255, 255, 255]]])

[[[127, 127, 127], [127, 127, 127]],

[[255, 255, 0], [255, 255, 0]],

[[0, 0, 255], [0, 0, 255]],

[[255, 0, 0], [255, 0, 0]]]

Answer 1

The input is not very clear in this problem. Is the shape of input [h, w, 2]?

I write a simple solution.

def mirror(arr):

for row in arr:

for i in range(len(row[0])):

row[1][i] = row[0][i]

return arr

arr = [[[127, 127, 127], [0, 0, 0]],

[[255, 255, 0], [50, 128, 255]],

[[0, 0, 255], [0, 255, 0]],

[[255, 0, 0], [255, 255, 255]]]

print(mirror(arr))

/*

output:

[[[127, 127, 127], [127, 127, 127]], [[255, 255, 0], [255, 255, 0]], [[0, 0, 255], [0, 0, 255]], [[255, 0, 0], [255, 0, 0]]]

*/