how many grams of H2O will be produced from 68.3 grams of C6H8O7?

Answer 1

This is a stoichiometric question regarding the combustion of a hydrocarbon. Follow these steps:

1. Write the skeleton equation for the complete combustion of C6H8O7
2. Remember that the generic equation is hydrocarbon + O2 gas -> CO2 + H2O
3. C₆H₈O₇ + O₂ -> CO₂ + H₂O
4. Write the balanced equation
5. 2C₆H₈O₇ + 4O₂ -> 12CO₂ + 8H₂O
6. Use stoichiometry to convert grams of ______ to grams of H₂O
7. Convert grams of C₆H₈O₇ to moles using molar mass
8. 68.3 g C₆H₈O₇ (1 mole C₆H₈O₇/192.14 g C₆H₈O₇) = 0.355 moles C₆H₈O₇
9. convert moles of C₆H₈O₇ to moles of H2O using mole ratio
10. according to the balanced equation there are 2 moles of C₆H₈O₇ for every 8 moles of water
11. 0.355 moles C₆H₈O₇ (8 mol H2O/ 2 mol C₆H₈O₇) = 1.42 mol H2O
12. convert moles of water to g of water using molar mass
13. 1.42 mol H2O (18.02g/1mol)= 25.6 grams H2O

Final answer: 25.6 grams H2O